Question #341343

The rational function f( 2/-2×-5)



A .Find f¹(×)



B. Find the equation of the line of symmetry of f¹(×) and f(×).


1
Expert's answer
2022-05-16T16:12:44-0400

A.


f(x)=22x5f(x)=\dfrac{2}{-2x-5}

2x50=>x2.5-2x-5\not=0=>x\not=-2.5

y=22x5y=\dfrac{2}{-2x-5}

Interchange xx and yy


x=22y5x=\dfrac{2}{-2y-5}

Solve for yy


2y+5=2x2y+5=-\dfrac{2}{x}

y=1x52y=-\dfrac{1}{x}-\dfrac{5}{2}

y=2+5x2xy=-\dfrac{2+5x}{2x}

Replace yy with f1(x)f^{-1}(x)


f1(x)=25x2xf^{-1}(x)=\dfrac{-2-5x}{2x}



B.

The line of symmetry of f1(x)f^{-1}(x) and f(x)f(x) is y=x.y=x.



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