Answer to Question #338424 in Algebra for Kaygee

Question

Tn=5n-4

Answer 1

$$T_n=5n-4=1+5(n-1)$$

Arithmetic progression: $T_1=1, d=5.$

$$S_n=\dfrac{1+5n-4}{2}\cdot n=\dfrac{5n^2-3n}{2}$$