Question #338424

Tn=5n-4


1
Expert's answer
2022-05-10T06:41:26-0400
Tn=5n4=1+5(n1)T_n=5n-4=1+5(n-1)

Arithmetic progression: T1=1,d=5.T_1=1, d=5.


Sn=1+5n42n=5n23n2S_n=\dfrac{1+5n-4}{2}\cdot n=\dfrac{5n^2-3n}{2}


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