A printing machine valued at $3000 depreciates at a constant rate of 18% per year. In how many years will the machine be worth $750?
y=A(d)xy=A(d)^xy=A(d)x
y=750
A=3000
d=1-0.18=0.82
x-?
750=3000(0.82)x750=3000(0.82)^x750=3000(0.82)x
(0.82)x=0.25(0.82)^x=0.25(0.82)x=0.25
x=7yearsx=7 yearsx=7years
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