Answer to Question #337391 in Algebra for Skyla

Question

A printing machine valued at $3000 depreciates at a constant rate of 18% per year. In how many years will the machine be worth $750?

Answer 1

$y=A(d)^x$

y=750

A=3000

d=1-0.18=0.82

x-?

$750=3000(0.82)^x$

$(0.82)^x=0.25$

$x=7 years$