Question #326076

An element with mass 820 grams decays by 26.8% per minute. How much of the element is remaining after 18 minutes, to the nearest 10th of a gram?


1
Expert's answer
2022-04-11T13:50:32-0400

Let m0=820 g,m_0 = 820 \space g,

α=26.8 %=0.268,\alpha = 26.8\space\% = 0.268,

T=18 min,T = 18\space min,

mtm_t - mass we have after time of decay tt


We have:

mt+1=mt(1α)m_{t + 1} = m_t(1 - \alpha)

This is a geometric progression with a common ratio equal to (1α)(1 - \alpha)

Its general term is represented by the formula mt=m0(1α)tm_t = m_0(1 - \alpha)^t


mT=m0(1α)T==820(10.268)18 g=3.0 gm_T = m_0(1 - \alpha)^T =\\ = 820\cdot(1 - 0.268)^{18}\space g = 3.0\space g


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