Gold is 19 times as heavy as water, copper is 9 times as heavy as water. in what ratio should these be mixed to get an alloy 15 times as heavy as water?
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Expert's answer
2013-06-26T07:30:04-0400
Suppose we have 1m^3 of water, 1m^3 of gold and 1m^3 of copper. Then we have for mass fractions 1 for water, 19 for gold and 9 for copper. We want to get 15 units of mass, so we need to get x m^3 of gold and 1-x m^3 of copper 19x+9(1-x)=15 19x+9-9x=15 10x=6 x=3/5 1-x=2/5 then we need to get 3 parts of gold and 2 parts of copper, so ratio is 3:2 gold to copper.
Comments
This is Algebra question.
Please, what category does this question #32394 belong?
The answer is absolutely correct. I did it and got the ration to be same. Thanks.
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