Answer to Question #323500 in Algebra for ild

Question #323500

1) Without fully expanding (4a-b)7, determine the fifth term.


2) Find the middle term of (2c - 12𝑑)10


1
Expert's answer
2022-04-06T10:34:25-0400

1:(4aβˆ’b)7The  fifth  term  (counting  from  0th  term)  is  C75(4a)5(βˆ’b)7βˆ’5=21504a5b22:(2cβˆ’12d)10The  middle  term  is  for  5th  powers:C105(2c)5(βˆ’12d)5=βˆ’2006581248c5d51:\\\left( 4a-b \right) ^7\\The\,\,fifth\,\,term\,\,\left( counting\,\,from\,\,0th\,\,term \right) \,\,is\,\,\\C_{7}^{5}\left( 4a \right) ^5\left( -b \right) ^{7-5}=21504a^5b^2\\2:\\\left( 2c-12d \right) ^{10}\\The\,\,middle\,\,term\,\,is\,\,for\,\,5th\,\,powers:\\C_{10}^{5}\left( 2c \right) ^5\left( -12d \right) ^5=-2006581248c^5d^5


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