Directions: find (f-g)(x) using the two functions given in each number.
1.f(x) =3 x
g(x) =-4x+1
2.f(x) =2x
g(x)= 4x2+2x-2
3.f(x) =5x+1
g(x) =3x
4.f(x) =5x+2
g(x)=3x-5
5.f(x) =3x
g(x) =4x²+5x-4
1:(f−g)(x)=3x−(−4x+1)=7x−12:(f−g)(x)=2x−(4x2+2x−2)=−4x2+23:(f−g)(x)=5x+1−3x=2x+14:(f−g)(x)=5x+2−(3x−5)=2x+75:(f−g)(x)=3x−(4x2+5x−4)=−4x2−2x+41:\\\left( f-g \right) \left( x \right) =3x-\left( -4x+1 \right) =7x-1\\2:\\\left( f-g \right) \left( x \right) =2x-\left( 4x^2+2x-2 \right) =-4x^2+2\\3:\\\left( f-g \right) \left( x \right) =5x+1-3x=2x+1\\4:\\\left( f-g \right) \left( x \right) =5x+2-\left( 3x-5 \right) =2x+7\\5:\\\left( f-g \right) \left( x \right) =3x-\left( 4x^2+5x-4 \right) =-4x^2-2x+41:(f−g)(x)=3x−(−4x+1)=7x−12:(f−g)(x)=2x−(4x2+2x−2)=−4x2+23:(f−g)(x)=5x+1−3x=2x+14:(f−g)(x)=5x+2−(3x−5)=2x+75:(f−g)(x)=3x−(4x2+5x−4)=−4x2−2x+4
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