You have 80 grams of a radioactive kind of tellurium. How much will be left after 8 months if its half-life is 2 months?
N(t)=N0(12)tt1/2=80⋅(12)82=5 g.N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}}=80\cdot(\frac{1}{2})^{\frac{8}{2}}=5\space g.N(t)=N0(21)t1/2t=80⋅(21)28=5 g.
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