Answer to Question #319101 in Algebra for Kealeboga

Question

X/2 + x/3 >17/6

Answer 1

$$\frac{x}{2}+\frac{x}{3}>\frac{17}{6}$$

Multiply both sides of the inequality by 6

$$3x+2x>17$$

$$5x>17$$

Now divide both sides of the inequality by 5

$$x>\frac{17}{5}$$