Question #317679

Create a logarithmic function in the form f(x) = loga(x + b) and find its inverse. Show all of your solution steps to earn full credit. Your answer must include:

  • A logarithmic function with a base value for a and a constant value for b
  • Steps showing how you found your function's inverse
  • The inverse function stated in function notation, -1(x)
1
Expert's answer
2022-03-29T05:09:50-0400


f(x)=loga(x+b)f(x)=log_{a}(x+b)


Let a=2,b=1a=2, b=1


f(x)=log2(x+1)f(x)=log_{2}(x+1)


let f(x)=yf(x)=y


=>y=log2(x+1)=>y=log_{2}(x+1)

=>2y=x+1=>2^{y}=x+1

=>x=2y1=>x=2^{y}-1

Hence, f1(x)=2x1f^{-1}(x)=2^{x}-1


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