The first term,seventh term and nth term of an AP are 4, 28 and 32 respectively. Calculate the number of terms in the sequence.
an=a1+(n−1)d.a_n=a_1+(n-1)d.an=a1+(n−1)d.
a1=4.a_1=4.a1=4.
a7=a1+(7−1)d→28=4+6d→d=4.a_7=a_1+(7-1)d\to 28=4+6d\to d=4.a7=a1+(7−1)d→28=4+6d→d=4.
an=4+4(n−1)→32=4+4(n−1)→n=8.a_n=4+4(n-1) \to 32=4+4(n-1) \to n=8.an=4+4(n−1)→32=4+4(n−1)→n=8.
There are 8 terms in the sequence.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments