Answer to Question #315861 in Algebra for lin

Question

A person throws a 755 g ball up at an angle such that it has an initial speed of 15.0 m s⁻¹. After a short time the ball has a speed of 5.30 m s⁻¹.

How much higher is the ball than when it was let go? (in m to 3 s.f) 

Answer 1

v₁= 15.0 ms^-1

v₂= 5.30 ms^-1

h = v₁²/(2g) - v₂²/(2g)

g = constant = 9.8 ms^-2

h = 15²/(2* 9.8) - 5.30²/(2* 9.8)

h = 11.47959 - 1.43316

h = 10.04643

h = 10 m (3 s.f)