for h(x) = 2/3 x -5 find the value of x for which h(x) = -7
Given that
h\left( x \right) = \frac{2}{3}x - 5\
Now for h\left( x \right) = - 7\
We have
\begin{gathered} h\left( x \right) = \frac{2}{3}x - 5 \\ \Rightarrow & - 7 = \frac{2}{3}x - 5 \\ \Rightarrow & - 7 \times 3 = \frac{2}{3}x \times 3 - 5 \times 3 \\ \Rightarrow & - 21 = 2x - 15 \\ \Rightarrow & - 21 + 15 = 2x \\ \Rightarrow & - 6 = 2x \\ \Rightarrow & x = - 3 \\ \end{gathered} \
Hence the value of for which is
We can write it as
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