Answer to Question #310369 in Algebra for Hatdog

Question

12 students have appeared in the exam in which the top four will get a prize. How many possible ways are there to get the prize winners?

Answer 1

Solution

This is a combination without repetition problem.

The number of Possible ways is given by $=\dbinom{12}{4}=\dfrac{12!}{4!(12-4)!}=495$

Possible ways to get the prize winners is $495$