Question #309693

Write the expression as a single logarithm.


4log6x-1/5 log6z + 2log6y



1
Expert's answer
2022-03-13T18:15:42-0400

4log6(x1)5log6z+2log6y\frac{4log_{6}(x-1)}{5log_{6}z+2log_{6}y}


=>log6(x1)4log6z5+log6y2=>\frac{log_{6}(x-1)⁴}{log_{6}z⁵+log_{6}y²}


=>log6(x1)4log6z5y2=>\frac{log_{6}(x-1)⁴}{log_{6}z⁵y²}


Recall that logxalogxb=logba\frac{log_{x} a}{log_{x}b} = log_{b}a


=>log6(x1)4log6z5y2=logz5y(x1)4=>\frac{log_{6}(x-1)⁴}{log_{6}z⁵y²}={log_{z⁵y}(x-1)⁴}








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