Is this correct:2a²b-ab-a=ab(2a-1)-a
ab(2a−1)−a=ab×2a−ab×1−a=2a2b−ab−aab(2a-1)-a=ab\times2a-ab\times1-a=2a^2b-ab-aab(2a−1)−a=ab×2a−ab×1−a=2a2b−ab−a
Yes, this is correct.
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