A straight line passes through the points (2; -3) and (4 - 4). The coordinate of the x intercept of this line is ?
Given points (2; -3) and (4, - 4).
Equation of line: y−y1=(y2−y1x2−x1)(x−x1)y-y_1=(\dfrac{y_2-y_1}{x_2-x1})(x-x_1)y−y1=(x2−x1y2−y1)(x−x1)
⇒y+3=(−4+34−2)(x−2)⇒y+3=(−12)(x−2)⇒2y+6=2−x\Rightarrow y+3=(\dfrac{-4+3}{4-2})(x-2) \\\Rightarrow y+3=(\dfrac{-1}{2})(x-2) \\\Rightarrow 2y+6=2-x⇒y+3=(4−2−4+3)(x−2)⇒y+3=(2−1)(x−2)⇒2y+6=2−x
For x-intercept, put y=0
⇒0+6=2−x⇒x=2−6⇒x=−4\Rightarrow 0+6=2-x \\\Rightarrow x=2-6 \\\Rightarrow x=-4⇒0+6=2−x⇒x=2−6⇒x=−4
x-intercept is (-4, 0).
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment