Answer to Question #299232 in Algebra for Philly

Question #299232

A straight line passes through the points (2; -3) and (4 - 4). The coordinate of the x intercept of this line is ?


1
Expert's answer
2022-02-20T16:57:45-0500

Solution:

Given points (2; -3) and (4, - 4).

Equation of line: yy1=(y2y1x2x1)(xx1)y-y_1=(\dfrac{y_2-y_1}{x_2-x1})(x-x_1)

y+3=(4+342)(x2)y+3=(12)(x2)2y+6=2x\Rightarrow y+3=(\dfrac{-4+3}{4-2})(x-2) \\\Rightarrow y+3=(\dfrac{-1}{2})(x-2) \\\Rightarrow 2y+6=2-x

For x-intercept, put y=0

0+6=2xx=26x=4\Rightarrow 0+6=2-x \\\Rightarrow x=2-6 \\\Rightarrow x=-4

x-intercept is (-4, 0).


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