find the value of x,
x2+2x+1=0
Solution;
x2+2x+1=0x^2+2x+1=0x2+2x+1=0
Rewrite as;
x2+x+x+1=0x^2+x+x+1=0x2+x+x+1=0
x(x+1)+1(x+1)=0x(x+1)+1(x+1)=0x(x+1)+1(x+1)=0
(x+1)(x+1)=0(x+1)(x+1)=0(x+1)(x+1)=0
Therefore;
x=−1x=-1x=−1
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