Question #298479

find the value of x,

x2+2x+1=0


Expert's answer

Solution;

x2+2x+1=0x^2+2x+1=0

Rewrite as;

x2+x+x+1=0x^2+x+x+1=0

x(x+1)+1(x+1)=0x(x+1)+1(x+1)=0

(x+1)(x+1)=0(x+1)(x+1)=0

Therefore;

x=1x=-1



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