Question #297019

Find the equation of the line.

Through (3,−5)​; perpendicular to y=−10.


Expert's answer

Explanations & Calculations


  • Equation of a line looks like y=mx+c\small y = mx+c
  • The line y=−10\small y = -10 is parallel to x−axis\small x- axis and since our line should be perpendicular to this, it should be parallel to y−axis\small y - axis hence should have the form x=px = p .
  • Since it lies on the given point, the line turns out to be x=3\small x = 3 .
  • This line lies on points −∞←(3,3), (3,4), (3,5), (3,6), (3,7)→+∞\small -\infty \leftarrow (3,3),\,(3,4),\,(3,5),\,(3,6),\,(3,7)\to+\infty
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