Answer to Question #295393 in Algebra for Math assignment

Question

16. Solve in |R:

(a) 2(3y-2)+3(4-3y)>12-(5y+7)

(b) 2(k+2)+3(2k-3)<or=2

17.(a) if x=1-3t and y=2t-1.

Find the value of t such that x=y.

(b) solve for real value of x the equation,

(m+1)x²-(m+3)x+3-m=0.

When m=-1.

18.Given the parametric equations:

x=t-1/t

y=2(t+2)/t²

Find the coordinates of the point where,

(a) t=-2

(b) t=-1

19.solve in |R:

(a) 4(m+5)-6(2m+3)=3(m+14)-2(5-m)+9

(b) 3(k-1)-4(k+6)=10(k+5)

Answer 1

16.

a)

$2(3y-2)+3(4-3y)>12-(5y+7)$

$6y-4+12-9y-12+5y+7>0$

$2y+3>0$

$y>-3/2$

(b)

$2(k+2)+3(2k-3)\le2$

$2k+4+6k-9\le 2$

$8k\le7$

$k\le7/8$

17.

(a)

$x=y=>1-3t =2t-1.$

$5t=2$

$t=2/5$

(b)

$(-1+1)x^2-(-1+3)x+3-(-1)=0$

$-2x+4=0$

$2x=4$

$x=2$

18.

(a)

$x=-2-1/(-2)=-3/2$

$y=2(-2+2)/(-2)^2=0$

Point $(-3/2, 0)$

(b)

$x=-1-1/(-1)=0$

$y=2(-1+2)/(-1)^2=2$

Point $(0, 2)$

19.

(a)

$4(m+5)-6(2m+3)=3(m+14)-2(5-m)+9$

$4m+20-12m-18=3m+42-10+2m+9$

$-8m+2=5m+41$

$13m=-39$

$m=-3$

(b)

$3(k-1)-4(k+6)=10(k+5)$

$3k-3-4k-24=10k+50$

$-k-27=10k+50$

$11k=-77$

$k=-7$