Find nth term of sequence (2)^2 , (5)^2,(8)^2.....
Answer in form(3n-1)^2
22,52,82...2^2, 5^2, 8^2...22,52,82...
2, 5, 8... the sequence is following the pattern (3n-1) where n is a natural number.
So, the sequence 22,52,82...2^2, 5^2, 8^2...22,52,82... will follow the pattern: (3n−1)2(3n-1)^2(3n−1)2 .
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