Find the equation of the straight line with gradient -1/2 that passes through the point (5,3)
The formula for equation of a line given the Slope "m" and point "(x_1,y_1)" is;
"\\displaystyle\nm=\\frac{y-y_1}{x-x_1}"
Here, "\\displaystyle\nm=-\\frac{1}{2},\\text{ and}(x_1,y_1)=(5,3)." Thus we have the equation of the line as;
"\\displaystyle\n-\\frac{1}{2}=\\frac{y-3}{x-5}\\Rightarrow y=-\\frac{x}{2}+\\frac{11}{2}"
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