Form the quadratic equation for which the sum of the roots is 5 and the sum of the squares of the roots is 53
Let the two roots be α\alphaα and β\betaβ.
α+β=5α2+β2=53\alpha +\beta=5\\ \alpha ^2+\beta^2=53α+β=5α2+β2=53
But,
(α+β)2=α2+β2+2αβ2αβ=(α+β)2−α2−β22αβ=52−53=−28αβ=−14(\alpha+\beta)^2=\alpha^2+\beta^2+2\alpha \beta\\ 2\alpha \beta=(\alpha+\beta)^2-\alpha^2-\beta^2\\ 2\alpha \beta=5^2-53=-28\\ \alpha \beta=-14(α+β)2=α2+β2+2αβ2αβ=(α+β)2−α2−β22αβ=52−53=−28αβ=−14
Quadratic equation with two roots α\alphaα and β\betaβ is given as:
x2−(α+β)x+αβ=0Substitute in the unknowns, we have the quadratic equation:x2−5x−14=0x^2-(\alpha+\beta)x+\alpha \beta=0\\ \text{Substitute in the unknowns, we have the quadratic equation:}\\ x^2-5x-14=0x2−(α+β)x+αβ=0Substitute in the unknowns, we have the quadratic equation:x2−5x−14=0
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