Form the quadratic equation for which the sum of the roots is 5 and the sum of the squares of the roots is 53
Let the two roots be "\\alpha" and "\\beta".
"\\alpha +\\beta=5\\\\\n\\alpha ^2+\\beta^2=53"
But,
"(\\alpha+\\beta)^2=\\alpha^2+\\beta^2+2\\alpha \\beta\\\\\n2\\alpha \\beta=(\\alpha+\\beta)^2-\\alpha^2-\\beta^2\\\\\n2\\alpha \\beta=5^2-53=-28\\\\\n\\alpha \\beta=-14"
Quadratic equation with two roots "\\alpha" and "\\beta" is given as:
"x^2-(\\alpha+\\beta)x+\\alpha \\beta=0\\\\\n\\text{Substitute in the unknowns, we have the quadratic equation:}\\\\\nx^2-5x-14=0"
Comments
Leave a comment