the equation x^2+bx+c=0 has roots -5 and 7. find the value of b and the value of c.
x2+bx+c=(x+5)(x−7).x^2+bx+c=(x+5)(x-7).x2+bx+c=(x+5)(x−7).
x2+bx+c=x2+(5−7)x−5∗7.x^2+bx+c=x^2+(5-7)x-5*7.x2+bx+c=x2+(5−7)x−5∗7.
x2+bx+c=x2−2x−35.x^2+bx+c=x^2-2x-35.x2+bx+c=x2−2x−35.
b=−2, c=−35.b=-2, \;c=-35.b=−2,c=−35.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments