Answer to Question #284943 in Algebra for Sunny

Question

 PROBLEM: 40 boys and 28 girls stand in a circle, hand in hand, all facing inward. Exactly 18 boys give their 

right hand to a girl. 

A. How many boys give their left hand toa a girl? 

B. What if 28 boys give their right hand to a girl? 

C. What will be your answer if both boys and girls are 28 in number?

Answer 1

A)How many boys give their left hand to a girl?

Total number of boys and girls$=40+28=68$

If 18 boys give their right hand to a girl,those who give their left hand becomes;

$40-22=18$

b)What if 28 boys give their right hand to a girl?

If 28 boys give their right hand,those who give their left hand will become;

$40-12=28$

C. What will be your answer if both boys and girls are 28 in number?

If both boys and girls are 28,the number of left hand will be 28