Question #28437

paula rode her bicycle in a 4-hour marathon. She passed the front rider after 12 minutes into the race. If her speed was constant throughout the race, how many meters did she ride before she passed the front rider?

Expert's answer

Paula rode her bicycle a total of 60 kilometers in a 4 hour marathon. She passed the front rider after 12 minutes into the race. If her speed was constant throughout the race, how many meters did she ride before she passed the front rider?

Solution

Let's find the velocity of the bicycle (we know that it's constant):


v=St=60 kilometers4 hour=601000 m46060 s=4.167msv = \frac {S}{t} = \frac {60 \text{ kilometers}}{4 \text{ hour}} = \frac {60 * 1000 \text{ m}}{4 * 60 * 60 \text{ s}} = 4.167 \frac{\text{m}}{\text{s}}


where S is a length of marathon, t is a time of marathon.

She ride before she passed the front rider X :


X=vt1=4.167ms12 minutes=4.1671260=3000 m=3 kmX = v * t_1 = 4.167 \frac{\text{m}}{\text{s}} * 12 \text{ minutes} = 4.167 * 12 * 60 = 3000 \text{ m} = 3 \text{ km}


where t is time she passed the front rider.

Answer: 3 km.

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