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Answer to Question #2840 in Algebra for Keyla
Question #2840
solving exponential equations with logarithms...
3^x=17
12^x=17
9^x=4.9
6^x= 0.51
18^2x=26
2^5x=34
3^x=17
12^x=17
9^x=4.9
6^x= 0.51
18^2x=26
2^5x=34
Expert's answer
x = log3 17
x = log12 17
x = log9 4.9
x = log6 0.51
x = ½ log18 26
x = 1/5 log2 34
x = log12 17
x = log9 4.9
x = log6 0.51
x = ½ log18 26
x = 1/5 log2 34
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