Answer to Question #2836 in Algebra for Keyla

Question

simplify each expression by rewriting it as a single logarithm
log X+ log Y+ log Z=
4 ln M + 21n N=
6 log A- 3 log B=
X log A + Y log B- (Z log C + W log D)=

Answer 1

log X + log Y + log Z = log XYZ
4 ln M + 2 ln N = ln M⁴N²
6 logA - 3 log B = log A⁶/B³
X log A + Y log B- (Z log C + W log D)= log A^X B^Y - log C^Z WD = log (A^X B^Y)/(C^ZW^D)