f(x) = (x⁴+3x³-2x²-x+7) / x-5, when x = 5?
"f(x) = \\frac{(x^4+3x^3-2x^2-x+7)}{x-5}"
At "x=5"
"f(5)=\\frac{(5^4+3(5)^3-2(5)^2-5+7)}{5-5}=\\infty"
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