Answer to Question #276108 in Algebra for Van

Question #276108

f(x) = (x⁴+3x³-2x²-x+7) / x-5, when x = 5?


1
Expert's answer
2021-12-07T06:40:19-0500

f(x)=(x4+3x32x2x+7)x5f(x) = \frac{(x^4+3x^3-2x^2-x+7)}{x-5}

At x=5x=5

f(5)=(54+3(5)32(5)25+7)55=f(5)=\frac{(5^4+3(5)^3-2(5)^2-5+7)}{5-5}=\infty


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