Answer to Question #275741 in Algebra for aiden

Question #275741

Jason estimates that his car loses 12% of its value every year. The initial value is $12,000. Which best describes the graph of the function that represents the value of the car after x years?

f(x) = 12,000(0.12)x, with a horizontal asymptote of y = 0

f(x) = 12,000(1.12)x, with a vertical asymptote of x = 0

f(x) = 12,000(0.88)x, with a horizontal asymptote of y = 0

f(x) = (12,000  0.88)x, with a vertical asymptote of x = 0


1
Expert's answer
2021-12-06T16:21:54-0500
f(x)=f(0)(1r)xf(x)=f(0)(1-r)^x

f(x)=12000(10.12)xf(x)=12000(1-0.12)^x

f(x)=12000(0.88)xf(x)=12000(0.88)^x

f(x)0 as xf(x)\to0\text{ as } x\to\infin

The horizontal asymptote is y=0.y=0.


f(x) = 12,000(0.88)x, with a horizontal asymptote of y = 0.


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