Question #275314

Find X in log6 x= ‐2


Expert's answer

Solution.

For equation logax=b\log_ax=b we find solution as x=ab.x=a^b.

So, we have

log6x=2\log_6x=-2x=62x=(16)2x=6^{-2}\newline x=(\frac{1}{6})^2x=136x=\frac{1}{36}

Answer. x=136.x=\frac{1}{36}.


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