Answer in Algebra for nazar luqman #275175

Question #275175

solve: /3x^2+2x/=x/3x+2/

Expert's answer

$3x^2+2x=\frac{x}{3x+2}\\ 9x^3+6x^2+6x^2+4x=x\\ 9x^3+12x^2+3x=0\\ 3x(3x^2+4x+1)=0\\ x(3x+1)(x+1)=0\\ x=0,-1,\frac{-1}{3}$

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