Answer to Question #273897 in Algebra for ann

Question

ways could we arrange so that marbles of the same color are together? In

how many ways could we pick 3 marbles so that one marble of each color

are picked ?

Answer 1

The number of marbles to be arranged are not given.

Assuming they are:

4 white

3 black

2 red

solution:

a). If the marbles of same colour are indistinguishable, any set of colour can take any of the position 1,2or 3

Number of ways$=3×2×1\\=6\>ways$

b) Drawing 3 marble so that we could have one one marble of each colour:

$=4×3×2×6\\=144\>ways$