Answer to Question #273266 in Algebra for Elise Landes

Question

Tickets for the homecoming dance cost $20 for a single ticket or $35 for a couple. Ticket sales totaled $2280, and 128 people attended. How many tickets of each type were sold? Be sure to define your variables first.

Answer 1

x - the number of single ticket

y - he number of couple ticket

$x + 2y=128 \to x = 128-2y$

$20x+35y=2280$

$20(128-2y)+35y=2280$

$2560-40y+35y=2280$

$5y=280 \to y = 56 \space \space and \space \space x = 128-2y=16$

Answer

56 - the number of single ticket

16 - the number of couple ticket