Question #272990

Completely factorize the following polynomial: x4−3x3+4x2−8


1
Expert's answer
2021-11-29T19:35:50-0500
x43x3+4x28x^4-3x^3+4x^2-8

=(x42x3)(x32x2)+(2x28)=(x^4-2x^3)-(x^3-2x^2)+(2x^2-8)

=x3(x2)x2(x2)+2(x2)(x+2)=x^3(x-2)-x^2(x-2)+2(x-2)(x+2)

=(x2)(x3x2+2x+4)=(x-2)(x^3-x^2+2x+4)

=(x2)((x3+x2)(2x2+2x)+(4x+4))=(x-2)((x^3+x^2)-(2x^2+2x)+(4x+4))

=(x2)(x+1)(x22x+4)=(x-2)(x+1)(x^2-2x+4)

=(x2)(x+1)(x2)2=(x-2)(x+1)(x-2)^2

=(x2)3(x+1)=(x-2)^3(x+1)

x43x3+4x28=(x+1)(x2)3x^4-3x^3+4x^2-8=(x+1)(x-2)^3


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