Question #272174

Solve the logarithmic equation 23x-2 =32x-1

1
Expert's answer
2021-11-29T13:22:31-0500
23x2=32x12^{3x-2} =3^{2x-1}

ln(23x2)=ln(32x1)\ln (2^{3x-2})=\ln (3^{2x-1})

(3x2)ln(2)=(2x1)ln(3)(3x-2)\ln (2)=(2x-1)\ln (3)

x(3ln(2)2ln(3))=2ln(2)ln(3)x(3\ln (2)-2\ln(3))=2\ln (2)-\ln(3)

x=ln(8/9)ln(4/3)x=\dfrac{\ln(8/9)}{\ln(4/3)}


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