a) The number of grams of a certain radioactive substance present after t hours is given by the equation Q = Q0e−0.45t, where Q0 represent the ini- tial number of grams. How long will it take 2500 grams to be reduced to 1250.
Given Q(t)=Q(0)e−0.45tWe solve for t to obtaine−0.45t=0.5Taking the log of both sides, we have−0.45t=ln(0.5)=−0.6931 ⟹ t=1.54hrs\displaystyle \text{Given }\\ Q(t)=Q(0)e^{-0.45t}\\ \text{We solve for t to obtain}\\ e^{-0.45t}=0.5\\ \text{Taking the log of both sides, we have}\\ -0.45t=\ln (0.5)=-0.6931\\ \implies t = 1.54 hrsGiven Q(t)=Q(0)e−0.45tWe solve for t to obtaine−0.45t=0.5Taking the log of both sides, we have−0.45t=ln(0.5)=−0.6931⟹t=1.54hrs
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