Consider the polynomial function š(š„) = 2š„^3 ā šš„^2 + š„ ā 5š. The remainder when P(x) is divided by (š„ ā 2) is four times the remainder from dividing P(x) by (š„ + 1). Determine m algebraically and show all your work.
Since x-2 and x+1 divides P(x), we have that at x = 2 and x = -1, therefore2(2)3ām(2)2+2ā5m=R(x)2(ā1)3ām(ā1)2+2ā5m=R(x)Therefore, we have 18ā9m=ā12ā24m15m=ā30ā āā¹ā ām=ā2\text{Since x-2 and x+1 divides P(x), we have that at x = 2 and x = -1, therefore}\\ 2(2)^3-m(2)^2+2-5m = R(x)\\ 2(-1)^3 - m (-1)^2+ 2 -5m=R(x)\\ \text{Therefore, we have }\\ 18-9m= -12-24m\\ 15m=-30\\ \implies m = -2Since x-2 and x+1 divides P(x), we have that at x = 2 and x = -1, therefore2(2)3ām(2)2+2ā5m=R(x)2(ā1)3ām(ā1)2+2ā5m=R(x)Therefore, we have 18ā9m=ā12ā24m15m=ā30ā¹m=ā2
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