Question #270259

Consider the polynomial function š‘ƒ(š‘„) = 2š‘„^3 āˆ’ š‘šš‘„^2 + š‘„ āˆ’ 5š‘š. The remainder when P(x) is divided by (š‘„ āˆ’ 2) is four times the remainder from dividing P(x) by (š‘„ + 1). Determine m algebraically and show all your work. 


Expert's answer

Since x-2 and x+1 divides P(x), we have that at x = 2 and x = -1, therefore2(2)3āˆ’m(2)2+2āˆ’5m=R(x)2(āˆ’1)3āˆ’m(āˆ’1)2+2āˆ’5m=R(x)Therefore, we have 18āˆ’9m=āˆ’12āˆ’24m15m=āˆ’30ā€…ā€ŠāŸ¹ā€…ā€Šm=āˆ’2\text{Since x-2 and x+1 divides P(x), we have that at x = 2 and x = -1, therefore}\\ 2(2)^3-m(2)^2+2-5m = R(x)\\ 2(-1)^3 - m (-1)^2+ 2 -5m=R(x)\\ \text{Therefore, we have }\\ 18-9m= -12-24m\\ 15m=-30\\ \implies m = -2


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