Examine the following steps in the solution to 5π₯2 β 5 = 0
5(π₯2 β 1) = 0
5(π₯ β 1)(π₯ + 1) = 0
π₯ β 1 = 0
or
π₯ + 1 = 0
π₯ = 1
π₯
= β1
What happened to 5? Explain.
5x2β5=05x^2β5=05x2β5=0
This is the given equation
5x2β5=05(x2β1)=0(x2β1)=05x2β1=0(x+1)(xβ1)=0x=1orx=β15x^2β5=0\\5(x^2β1)=0\\(x^2β1)=\frac{0}{5}\\x^2β1=0\\(x+1)(xβ1)=0\\x=1 \\or\\ x=β15x2β5=05(x2β1)=0(x2β1)=50βx2β1=0(x+1)(xβ1)=0x=1orx=β1
5 got divided by 0
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