Question

first five brothers were given land with area l03,107,105,90 and 95m². if the mean of the areas of land is 105m² who received the biggest share

Answer 1

first brother's share: 107 m²

second brother's share: 105 m²

third brother's share: 90 m²

fourth brother's share: 95 m²

fifth brother's share: x

mean of the areas of land = 105 m²

$\dfrac{107 + 105 + 90 + 95 + x}5 = 105$

$397+x = 525\\ x = 525- 397\\ x = 128$

the fifth brother's share is therefore 128 m².

$\therefore$ The fifth brother gets the largest share$.$