If log𝑎 𝑞 = 1/5 solve the equation , 𝑥 log𝑎 𝑞 + (𝑥 + 2) log𝑎 𝑞^2 = 3
xlogaq+(x+2)ogaq2=3x×15+2(x+2)logaq=3x×15+2(x+2)×15=315(x+2x+40=33x+4=15x=113xlog_aq+(x+2)og_aq^2=3\\x\times \frac{1}{5}+2(x+2)log_aq=3\\x\times\frac{1}{5}+2(x+2)\times\frac{1}{5}=3\\\frac{1}{5}(x+2x+40=3\\3x+4=15\\x=\frac{11}{3}xlogaq+(x+2)ogaq2=3x×51+2(x+2)logaq=3x×51+2(x+2)×51=351(x+2x+40=33x+4=15x=311
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