Question #262595

Find the slope-intercept form for the line perpendicular to 2x –3y=-6 and passing through (4,–9)


1
Expert's answer
2021-11-08T17:34:00-0500

For perpendicular lines, m1m2=1m_1m_2 = -1


From 2x3y=62x-3y=-6 , we have that y=23x+2y=\frac{2}{3}x+2


Let m1=23m_1=\frac{2}{3}

=> m2=32m_2=\frac{-3}{2}


m2=yy1xx1m_2=\frac{y-y_1}{x-x_1}



32=y(9)x4=y+9x4\frac{-3}{2}=\frac{y-(-9)}{x-4}=\frac{y+9}{x-4}


=> 3(x4)=2(y+9)-3(x-4)=2(y+9)

123x=2y+1812-3x=2y+18


=>y=32x3=> y = \frac{-3}{2}x-3


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