Solution;
f(x)=x−12x+1
Domain;
Means x−1=0 hence,x=1
The domain of f(x) is all real values expect -1.
Range;
Let f(x)=x−12x+1=y
2x+1=y(x−1)
2x+1=yx−y
2x−yx=−1−y
x(2−y)=−1−y
x=2−y−1−y
Means that the quantity 2−y=0
Hence;
y=2
The range of f(x) is all real values except 2.
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