Answer to Question #261958 in Algebra for Lily

Question

During an experiment in the lab jack a biologist has a 40%miture and a 10% mixture of the nutrient that he got from the pawpaw plant. The lecturer posed the question to jack. How much if each mixture should jack mix to obtain 25cm^3 of a 28% mixture

Answer 1

Jack need 15 cm³ of 40% and 10 cm³ of 28% mixture.

Let $x$ represent amount of first mixture and $y$ represent the amount of second mixture.

Then the first equation (eq1) states, that total volume is 25 cm³.

There are 0.4 x grams of the nutrient in x cm³ of 40% mixture.

Accordingly, there are 0.1 y and 0.28×25 grams of the nutrient in y and 25 cm³.

So the second equation is based on that fact. The total solution in Mathematica is shown below: