Answer to Question #261626 in Algebra for Kayla

Question

Construct a table of values of the following functions using the interval of -5 to 5

j(t)=1/t²-2t+1

Answer 1

$$j(t)=\dfrac{1}{t^2-2t+1}=\dfrac{1}{(t-1)^2}$$

$$\def\arraystretch{1.5} \begin{array}{c:c} t & j(t)\\ \hline -5 & 1/36 \\ \hdashline -9/2 & 4/121\\ \hdashline -4 & 1/25 \\ \hdashline -7/2 & 4/81\\ \hdashline -3 & 1/16 \\ \hdashline -5/2 & 4/49\\ \hdashline -2 & 1/9 \\ \hdashline -3/2 & 4/25\\ \hdashline -1 & 1/4\\ \hdashline -1/2 & 4/9\\ \hdashline 0 & 1\\ \hdashline 1/2 & 4\\ \hdashline 1 & undefined\\ \hdashline 3/2 & 4\\ \hdashline 2 & 1\\ \hdashline 5/2 & 4/9\\ \hdashline 3 & 1/4\\ \hdashline 7/2 & 4/25\\ \hdashline 4 & 1/9\\ \hdashline 9/2 & 4/49\\ \hdashline 5 & 1/16\\ \end{array}$$