Find the inverse function of g(x)=(x+2)³
g(x)=(x+2)3let y=g(x)=(x+y)3y=(x+2)3y13=x+2x=y13−2x=y3−2g−1(y)=xg−1(y)=y3−2g−1(x)=x3−2g(x)=(x+2)^3\\let\space y=g(x)=(x+y)^3\\y=(x+2)^3\\y^{\frac{1}{3}}=x+2\\x=y^{\frac{1}{3}}-2\\x=\sqrt[3]{y}-2\\g^{-1}(y)=x\\g^{-1}(y)=\sqrt[3]{y}-2\\g^{-1}(x)=\sqrt[3]{x}-2\\g(x)=(x+2)3let y=g(x)=(x+y)3y=(x+2)3y31=x+2x=y31−2x=3y−2g−1(y)=xg−1(y)=3y−2g−1(x)=3x−2
inverse=x3−2\sqrt[3]{x}-23x−2
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