Use the half-life decay model as follows:
A=A0(12)−th=A02−thA = A _{0}(\frac{1}{2})\\^\frac{-t}{h} \\= A _{0}2^\frac{-t}{h}A=A0(21)h−t=A02h−t
Using A0=100A _{0} = 100A0=100 and h=46.5h = 46.5h=46.5, we obtain:
100(2−t46.5)100(2^\frac{-t}{46.5})100(246.5−t)
After 24 hours:
100(2−2446.5)=69.9245 milligrams100(2\\^\frac{-24}{46.5})\\= 69.9245 \ milligrams100(246.5−24)=69.9245 milligrams
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments