Let us determine a,b,ca,b,ca,b,c of the quadratic equation 2x2+4x=8.2x²+4x=8.2x2+4x=8. The equation 2x2+4x=82x²+4x=82x2+4x=8 is equivalent to 2x2+4x−8=0,2x²+4x-8=0,2x2+4x−8=0, and hence a=2,b=4,c=−8.a=2, b=4, c=-8.a=2,b=4,c=−8.
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