Answer to Question #254883 in Algebra for Kat

Question

In a 51-inch television,the length of the screen’s height is 25 inches ,what is the width?round your answer to the nearest tenth of an inch

Answer 1

Here, TV screen sizes are specified according to their diagonal measurements, so if it's 25 inches tall,

Let w= width and h= height

Then

$w^2+25^2=51^2\\w^2=51^2-25^2\\w^2=2601-625\\w^2=1976\\w=\sqrt{1976}\\w=44.45\space inches$