Answer to Question #254722 in Algebra for Jamie

Question

w^2-1/2w-6÷w^2+w-2/3w-9

Answer 1

$w^2-1/2w-6÷w^2+w-2/3w-9$

$w^2-1/2w-6/w^2+w-2/3w-9$

Simplify

$w^2-\frac{1}{2}w-\frac{6}{w^2}+w-\frac{2}{3}w-9$

$w^2-\frac{1}{6}w-\frac{6}{w^2}-9$

$Lcm =2×w^2×3=6w^2$

$\frac{6w^4-w^3-36-54w^2}{6w^2}$

Hence = $\frac{6w^4-w^3-54w^2-36}{6w^2}$