Answer to Question #254722 in Algebra for Jamie

Question #254722
w^2-1/2w-6÷w^2+w-2/3w-9
1
Expert's answer
2021-10-22T00:44:54-0400

w21/2w6÷w2+w2/3w9w^2-1/2w-6÷w^2+w-2/3w-9


w21/2w6/w2+w2/3w9w^2-1/2w-6/w^2+w-2/3w-9


Simplify


w212w6w2+w23w9w^2-\frac{1}{2}w-\frac{6}{w^2}+w-\frac{2}{3}w-9


w216w6w29w^2-\frac{1}{6}w-\frac{6}{w^2}-9


Lcm=2×w2×3=6w2Lcm =2×w^2×3=6w^2


6w4w33654w26w2\frac{6w^4-w^3-36-54w^2}{6w^2}


Hence = 6w4w354w2366w2\frac{6w^4-w^3-54w^2-36}{6w^2}



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